Video over the Network

edit

After months of searching the internet, this is what I came up with, I have neatly packaged it into classes, with unit tests and documentation as SmoothStream check it out, it was the only simple and working version of streaming I could find anywhere.

I used this code and wrapped mine around it.

Viewer.py

import cv2
import zmq
import base64
import numpy as np

context = zmq.Context()
footage_socket = context.socket(zmq.SUB)
footage_socket.bind('tcp://*:5555')
footage_socket.setsockopt_string(zmq.SUBSCRIBE, np.unicode(''))

while True:
    try:
        frame = footage_socket.recv_string()
        img = base64.b64decode(frame)
        npimg = np.fromstring(img, dtype=np.uint8)
        source = cv2.imdecode(npimg, 1)
        cv2.imshow("Stream", source)
        cv2.waitKey(1)

    except KeyboardInterrupt:
        cv2.destroyAllWindows()
        break

Streamer.py

import base64
import cv2
import zmq

context = zmq.Context()
footage_socket = context.socket(zmq.PUB)
footage_socket.connect('tcp://localhost:5555')

camera = cv2.VideoCapture(0)  # init the camera

while True:
    try:
        grabbed, frame = camera.read()  # grab the current frame
        frame = cv2.resize(frame, (640, 480))  # resize the frame
        encoded, buffer = cv2.imencode('.jpg', frame)
        jpg_as_text = base64.b64encode(buffer)
        footage_socket.send(jpg_as_text)

    except KeyboardInterrupt:
        camera.release()
        cv2.destroyAllWindows()
        break

like Spas Hristov said, cv.CaptureFromCAM(int id) is used for (local) cameras, not for streams/urls.

try:

   import cv2
   import numpy

   cap = cv2.VideoCapture("http://@192.168.1.6:86/")
   while cap.isOpened():
       _,frame = cap.read()
       cv2.imshow("stream",frame)
       c = cv2.waitKey(1)
       if c == 27:
           break

Very clear that it will give error...

CvCapture* cvCaptureFromCAM(int index)

Initializes capturing a video from a camera.
Parameter:    index – Index of the camera to be used. If there is only

one camera or it does not matter what camera is used -1 may be passed.

try that LINK

p.p. code, found somewhere... for example:

//MJPEG network stream to OpenCV 2

#include "opencv/cv.h"
#include "opencv/highgui.h"
#include <iostream>

int main(int, char**) {
    cv::VideoCapture vcap;
    cv::Mat image;

    const std::string videoStreamAddress = "ip.ip.ip.ip";

    if(!vcap.open(videoStreamAddress)) {
        std::cout << "Error opening video stream or file" << std::endl;
        return -1;
    }

    for(;;) {
        if(!vcap.read(image)) {
            std::cout << "No frame" << std::endl;
            cv::waitKey();
        }
        cv::imshow("Output Window", image);
        if(cv::waitKey(1) >= 0) break;
    }   
}