Signal in frequency domain with OpenCV dft

asked 2018-10-13 08:01:16 -0500

t3rb3d gravatar image

updated 2018-10-13 09:24:55 -0500

I am experimenting with cv::dft: a 1HZ sinus signal is generated, and displayed in the frequency domain. But for some reason it hasn't got the maximum component at 1Hz. My code is the following:

       const int FRAME_RATE = 20;             //!< sampling rate in [Hz]
       const int WINDOW_SIZE = 256;         

       double len = double(WINDOW_SIZE)/double(FRAME_RATE);   // signal length in seconds
       double Fb = 1./len;                                     // frequency bin in Hz

       // Constructing frequency vector
       std::vector<double> f;
       double freq_step = 0;
       for (int i = 0; i < WINDOW_SIZE; ++i)
       {
             f.push_back(freq_step);
             freq_step += Fb;
       }


   // Create time vector
   std::vector<double> t;
   double time_step = 0;
   for(int i = 0; i<WINDOW_SIZE; ++i)
   {
       t.push_back(time_step);
       time_step += 1./double(FRAME_RATE);
   }

   // Creating sin signal with 1Hz period
   std::vector<double> y;
   for(auto val : t)
   {
       y.push_back(sin(1*FRAME_RATE*val));
   }

   // Compute DFT
   cv::Mat fd;
   cv::dft(y, fd, cv::DFT_REAL_OUTPUT);
   fd = cv::abs(fd);

If I plot the signal in time and frequency domain: plot(t, y); plot(f, fd) the result is the following:

enter image description here

The time signal is good, but the frequency signal has maximum around 6HZ instead of 1HZ.

Where did I take the mistake?

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Comments

Can you please upload your entire code? For instance, I get the error: dft.cpp(43): error C3861: 'plot': identifier not found.

PS. This is a very interesting problem. Please allow me to help as best I can, with your entire code.

sjhalayka gravatar imagesjhalayka ( 2018-10-13 18:00:59 -0500 )edit

Yes, the plot is not an existing function, only denotes that if I plot them in some way . Since than I figured it out, and I will post the result. Thank you for your reply!

t3rb3d gravatar imaget3rb3d ( 2018-10-15 04:09:19 -0500 )edit

Frequency is one : sin(1FRAME_RATEval) No : sin(2pi1FRAME_RATEval)

LBerger gravatar imageLBerger ( 2018-10-15 07:51:52 -0500 )edit

Yes, and also cv::dft(y, fd, cv::DFT_REAL_OUTPUT); yields 0:Fs/2 Hz range, where Fs is the sampling rate!

t3rb3d gravatar imaget3rb3d ( 2018-10-19 04:11:00 -0500 )edit

What do you mean cv::dft(y, fd, cv::DFT_REAL_OUTPUT); ? I cannot understand this flag for direct transform

LBerger gravatar imageLBerger ( 2018-10-19 06:14:25 -0500 )edit

I think if you use this flag, the output is just the real part of the fft. The output is the same length, but there is no information in the second half segment, it is padded with zeros, and the first half contains the frequency components in 0:Fs/2 Hz range.

t3rb3d gravatar imaget3rb3d ( 2018-10-19 08:17:31 -0500 )edit

I remember now why I never use DFT_REAL_OUTPUT :

Mat x = (Mat_<double>(1, 8) << 1, 1, 0, 0, 0, 0, 0, 0);
Mat X;
dft(x, X, DFT_REAL_OUTPUT);
cout << "Signal " << x << endl;
cout << "DFT_REAL_OUTPUT DFT(x)=X " << X << endl;
dft(x, X,DFT_COMPLEX_OUTPUT);
cout << "Signal " << x << endl;
cout << "DFT_COMPLEX_OUTPUT DFT(x)=X " << X << endl;

results

LBerger gravatar imageLBerger ( 2018-10-19 08:54:42 -0500 )edit
1

Results :

Signal [1, 1, 0, 0, 0, 0, 0, 0]
DFT_REAL_OUTPUT DFT(x)=X [2, 1.707106781186547, -0.7071067811865475, 1, -1, 0.2928932188134524, -0.7071067811865475, 0]
Signal [1, 1, 0, 0, 0, 0, 0, 0]
DFT_COMPLEX_OUTPUT DFT(x)=X [2, 0, 1.707106781186547, -0.7071067811865475, 1, -1, 0.2928932188134524, -0.7071067811865475, 0, 0, 0.2928932188134524, 0.7071067811865475, 1, 1, 1.707106781186547, 0.7071067811865475]

You must use the doc to understand result : packed format called CCS

LBerger gravatar imageLBerger ( 2018-10-19 08:57:51 -0500 )edit