风飞向何处's profile - activity

thank you very mach! I have get webcam .I'm using ubuntu os . the ffmpeg is a encoding lib . it is using for linux not windows , so I think there is some error with my vs 2010 not ffmpeg

Mat grains(480,640,CV_8UC3,Scalar::all(0)); const string videoStreamAddress1 = "http://devimages.apple.com/iphone/samples/bipbop/bipbopall.m3u8?dummy=param.mjpg"; //From mjpeg streamer const string videoStreamAddress2 = "http://devimages.apple.com/iphone/samples/bipbop/gear1/prog_index.m3u8?dummy=param.mjpg"; //From mjpeg streamer

if(!vcap1.open(videoStreamAddress1)) { cout << "Error opening video stream1" <<endl; }
after execute this cord the screen print Error opening video stream1 , if i'm using browser I can capture webcam. but can't capture using vs2010

thanks! I'm using your cord: cap.open("http://devimages.apple.com/iphone/samples/bipbop/bipbopall.m3u8dummy=param.mjpg"); the URL can open in browser,but can not open in vs2010 use you code :cap.open(URL); whether should I do some setting with my vs2010 ? or the version problem of my opencv . my opencv version is 2.3.0

is there have a OpenCV API to get picture from web?the　URL is http://192.168.1.200:8080/action=snapshot

thinks for your replay! my compiler is vs2010 , I used your method! but I can't succeed. whether should i do some setting?

how should I do, if I using the Compiler vs2010 read web camera？ the web IP is 192.168.1.180/?action=stream . I can see the picture from IE. whether should set vs2010?

Is there have a API we can use to get video stream from web. For example from 192.168.1.180/?action=stream.

I have found the answer. in the version 2.4.0 have the class stitcher.

thank you for you help！！！

who can tell me which version have stitcher class. the version 2.4.0 have it ?

I want make a binary image . the code is the following:

#include<opencv\cv.h>
#include<stdlib.h>
#include<opencv2\opencv.hpp>
#include<opencv\highgui.h>
using namespace cv;
int main()
{
    int i=0,j=0;
    Mat img = imread("hh.jpg");
    if(img.empty())
    {
        printf("无法打开\n");
        return 0;
    }
    for(i=0;i<img.rows;++i)
        for(j=0;j<img.cols;++j)
        {
            if(img.at<uchar>(i,j)>=230)
                img.at<uchar>(i,j)=255;
            else
                img.at<uchar>(i,j)=0;
        }

    imshow("图片浏览",img);
    waitKey();
    return 0;
}