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Thank you for the scaling factor. As for the double precision, apparently some openCV functions I want to use are made for the CV_32F type only. I am using the 2.4.1 version, but maybe it has been rectified after. The only remaining problem is about the display of the result (convertTo's first parameter).

My program needs more accuracy (filtering, reduction by the average... this kind of operations). So the first thing I need is to use floating points. But the behavior I have, just by converting it, is unexpected. And since 32 = 8 x 4, why does it display half of my image?

Hi,

I am not really familiar with openCV, so I am probably using its functions wrong.

The code is as follows.

cv::Mat im0Bgr = cv::imread("colormapTest.png"); // 32x32 test image

cv::Mat im0BgrDouble;

im0Bgr.convertTo(im0BgrDouble, CV_32F);

// Then //

cv::namedWindow("Figure 1");

cv::namedWindow("Figure 2");

cv::imshow("Figure 1", im0Bgr);

cv::imshow("Figure 2", im0BgrDouble);

//... and destroyed just after

My original image is of type CV_8U. It is displayed correctly. My converted image is supposed to be in the range [0,1], while it is not ([0,255] instead). More than that, only the half top part is displayed, and the bottom half is displayed white, though the converted object contains some 0 there.

Can someone point out where I am mistaken? I guess such a simple thing does not come from OpenCV. Thank you.