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Hi all, I'm new with OpenCV and a have a dude with calibrationMatrixValues. I have a program in C++ I want to calculate the maximum width and height that captures the WebCam to 50cm. I thought calculate using the FOV, for that I have calibrated the camera with a chessboard, as explained here: http://docs.opencv.org/doc/tutorials/calib3d/camera_calibration/camera_calibration.html#cameracalibrationopencv I invoke calibrationMatrixValues by passing the matrix ​​calculated . He tells me fovx = 44.68 and fovy = 34'26. I've been doing various tests and looking in different forums, and I can not understand how to calculate it. I think it's just trigonometry, but do not know if what the function returns well, because I've gotta figure values ​​were incorrect. (I should get out more or less about 60 cm) Any help you can give me would be appreciated, Sorry for my bad english. A greeting.

Hi all, I'm new with OpenCV and a have a dude with calibrationMatrixValues. I have a program in C++ calibrationMatrixValues.
I want to calculate the maximum width and height that captures the my WebCam to 50cm. I thought calculate using the FOV, for that I have calibrated the camera with a chessboard, as explained here: http://docs.opencv.org/doc/tutorials/calib3d/camera_calibration/camera_calibration.html#cameracalibrationopencv here:
http://docs.opencv.org/doc/tutorials/calib3d/camera_calibration/camera_calibration.html#cameracalibrationopencv
I invoke calibrationMatrixValues by passing the matrix ​​calculated . He ​​calculated. I don't know if this its correct

FileStorage fs2("out_camera_data.xml", FileStorage::READ);
  Mat cameraMatrix2;
  fs2["Camera_Matrix"] >> cameraMatrix2;
  cv::Size imageSize(640,480);
  double apertureWidth = 1;
  double apertureHeight = 1;
  double fieldOfViewX;
  double fieldOfViewY;
  double focalLength;
  cv::Point2d principalPoint;
  double aspectRatio;
  cv::calibrationMatrixValues(cameraMatrix2, imageSize, apertureWidth, apertureHeight, fieldOfViewX, fieldOfViewY, focalLength, principalPoint, aspectRatio);

Whats the apertureWidth/height mean? Are they correct? When I run this, he tells me fovx = 44.68 and fovy = 34'26. 34.26.These results would be corrects?
I've been doing various tests and looking in different forums, and I can not understand how can't understand.
I try to calculate it. I think it's just trigonometry, but get the values I need with these values and I do not know if what the function returns well, I'm wrong ( with my trigonometry calculations) or its because I've gotta figure values ​​were incorrect. (I I call wrong the function. I should get out more or less about 60 cm) cm of width
Any help you can give me would be appreciated, appreciated,
Sorry for my bad english.
A greeting.