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How to use cv2.xphoto.inpaint in Python3

asked 2019-04-16 09:49:57 -0500

DaveK gravatar image

updated 2019-04-17 04:26:45 -0500

I'm trying to inpaint an image using cv2.xphoto.inpaint in Python 3, however it just produces a zero image. I installed opencv=3.4.2 via conda. The docs say the images need to be in Lab colorspace, however I get the same result with RGB.

My code:

import cv2
import numpy as np
from scipy.misc import imread
import matplotlib.pyplot as plt

cow = imread('C:/cow.png')
mask = imread('C:/mask.png')

img_lab = cv2.cvtColor(src=cow, code=cv2.COLOR_RGB2Lab)
inverse_mask = np.uint8(np.max(mask == 255, axis=-1))

dst = np.zeros_like(cow)
cv2.xphoto.inpaint(src=img_lab, mask=inverse_mask, dst=dst, algorithmType=cv2.xphoto.INPAINT_SHIFTMAP)
dst = cv2.cvtColor(src=dst, code=cv2.COLOR_Lab2RGB)


Used images:

image description image description

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2 answers

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answered 2020-01-06 08:40:48 -0500

zeit gravatar image

updated 2020-01-09 21:03:05 -0500

I modified your codes and it worked!

Hope my codes will help you.

import cv2
import numpy as np

if __name__ == "__main__":
    s_img_src = 'source.jpg'
    s_img_mask = 'mask.png'

    img_src = cv2.imread(s_img_src)
    img_src_lab = cv2.cvtColor(img_src, cv2.COLOR_BGR2Lab)

    img_mask = cv2.imread(s_img_mask, cv2.IMREAD_GRAYSCALE)
    img_mask_inv = cv2.bitwise_not(img_mask)

    img_dst = np.zeros_like(img_src)
    cv2.xphoto.inpaint(img_src_lab, img_mask_inv, img_dst,
    img_dst = cv2.cvtColor(img_dst, cv2.COLOR_Lab2BGR)

    cv2.imshow('temp', img_dst)

source mask


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answered 2019-04-16 10:26:09 -0500

LBerger gravatar image

updated 2019-04-17 05:21:43 -0500

there is sample here White = good pixels and Black unknow pixel : inpaintMask Inpainting mask, 8-bit 1-channel image. Non-zero pixels indicate the area that needs to be inpainted.

Now in xphoto : in c++

    Mat img = imread("g:/lib/opencv/samples/data/lena.jpg");
    Mat mask(img.size(),CV_8UC1,Scalar(255));
    circle(mask, Point(256, 256), 50, Scalar(0), -1);
    Mat res;
    cv::xphoto::inpaint(img, mask, res, cv::xphoto::INPAINT_SHIFTMAP);
    imshow("shiftmap", res);

results is

image description

Same program in python

import numpy as np
import cv2 as cv
img = cv.imread('g:/lib/opencv/samples/data/lena.jpg')
mask = 255 * np.ones((img.shape[0],img.shape[1]),np.uint8)
mask =,(256,256),0,-1)
res = np.zeros(img.shape,np.uint8)

result is an empty image

image description

You should post an issue python binding is wrong and mask must be modify to use same definition

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Are you also using opencv=3.4.2 in c++?

DaveK gravatar imageDaveK ( 2019-04-17 02:05:04 -0500 )edit

No opencv 4.1-dev

LBerger gravatar imageLBerger ( 2019-04-17 04:35:19 -0500 )edit

Ok, I also tried it with pip opencv-contrib-python- with the same result. Thanks for your efforts.

DaveK gravatar imageDaveK ( 2019-04-17 04:36:39 -0500 )edit

There is a bug in python binding. If you can compile opencv and opencv_contrib and python binding then it can be solved

LBerger gravatar imageLBerger ( 2019-04-17 04:51:31 -0500 )edit

I just noticed some problems in your python code. It seems you forgot to specify a radius for the circle?

mask =, (256, 256), 50, 0, -1)

Also the line

res = np.array(img.shape,np.uint8)

creates an array of the shape tuple itself. Not a new array of this shape. You have to use np.zeros instead.

And while I checked your code, I randomly tried to use a 255, 0 mask instead of a 1, 0 mask which fixed the issue.

The following works for me now:

img = imread('C:/ma/lenna.png')
mask = 255 * np.ones((img.shape[0], img.shape[1]), np.uint8)
mask =, (256, 256), 50, 0, -1)
res = np.zeros(img.shape, np.uint8)
cv.xphoto.inpaint(img, mask, res, cv.xphoto.INPAINT_SHIFTMAP)

DaveK gravatar imageDaveK ( 2019-04-17 04:52:30 -0500 )edit

The doc states the following:

mask: (CV_8UC1), where non-zero pixels indicate valid image area, while zero pixels indicate area to be inpainted

which seems to be wrong. I'll open an issue for that.

DaveK gravatar imageDaveK ( 2019-04-17 04:54:40 -0500 )edit

Too much copy and paste gives error

LBerger gravatar imageLBerger ( 2019-04-17 05:00:02 -0500 )edit
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Asked: 2019-04-16 09:49:57 -0500

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Last updated: Jan 09