read and display image of large size

asked 2019-03-19 11:22:30 -0600

lzlu123
1 ●1 ●1

I have images of size 1.1 - 1.5 G that need to be loaded and processed, then displayed. When I load the image, I get the following error:

OpenCV: terminate handler is called! The last OpenCV error is: OpenCV(4.1.0-pre) Error: Assertion failed (pixels <= CV_IO_MAX_IMAGE_PIXELS) in cv::validateInputImageSize, file C:\openCV\opencv\modules\imgcodecs\src\loadsave.cpp, line 75

I try to change the default size settings in the code but still get error. What should I do to load images of such size? My computer has plenty of memory, even matlab can load the image without issue.

Thanks in advance

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what have you tried?

"I try to change the default size settings in the code" no you must set CV_IO_MAX_IMAGE_PIXELS) variable in shell and run your program

LBerger ( 2019-03-19 11:27:35 -0600 )edit

Hi,

I did both, in shell to set an environment variable and in source. none of them works.

lzlu123 ( 2019-03-19 13:29:36 -0600 )edit

without any code or method I cannot reproduce your problem. Opencv version platform ?

LBerger ( 2019-03-19 13:58:28 -0600 )edit

Hi,

My code is very simple to reproduce the problem: int main(int argc, char** argv) { // ... Mat image; image = imread(argv[1], IMREAD_COLOR); // Read the file namedWindow("Display window", WINDOW_NORMAL); resizeWindow("Display frame", 1024, 1024); imshow("Display window", image); // Show our image inside it. waitKey(0); // Wait for a keystrok

lzlu123 ( 2019-03-19 14:30:58 -0600 )edit

before running, at command line, set CV_IO_MAX_IMAGE_PIXELS=18500000000

I use the master branch head.

Thanks

lzlu123 ( 2019-03-19 14:33:21 -0600 )edit

oops I made a mistake

LBerger ( 2019-03-19 14:38:54 -0600 )edit

Hi, Thanks a lot for you spending effort on this issue. I dig a little bit deeper: 1. When I set the environment variable CV_IO_MAX_IMAGE_PIXELS to very large number, it saturates to 1073741824 on my Windows 10.
2. If I modify the source code to change

static const size_t CV_IO_MAX_IMAGE_PIXELS = utils::getConfigurationParameterSizeT("OPENCV_IO_MAX_IMAGE_PIXELS", 1 << 30);

static const size_t CV_IO_MAX_IMAGE_PIXELS = utils::getConfigurationParameterSizeT("OPENCV_IO_MAX_IMAGE_PIXELS", 1 << 34);

The CV_IO_MAX_IMAGE_PIXELS will be zero! It appears that the system limits to 32 bit, but I don't know. I am very new to openCV and just getting start to get my feet wet.

Thanks again.

lzlu123 ( 2019-03-19 15:31:47 -0600 )edit

Opencv version platform ? and don't change source code

LBerger ( 2019-03-19 15:41:00 -0600 )edit

OpenCV version: 4.1.0-pre OpenCV VCS version: 4.0.1-413-g17ad33c91 Windows 10, Visual Studio pro 15.9.8

lzlu123 ( 2019-03-20 08:10:00 -0600 )edit

thank you so much @lzlu123 i solved my problem

Duc23 ( 2020-07-14 09:41:56 -0600 )edit

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answered 2019-03-19 14:40:11 -0600

LBerger
9317 ●2 ●20 ●88 http://www.traimaocv.fr

You must set OPENCV_IO_MAX_IMAGE_PIXELS before your script

Microsoft Windows [version 10.0.17763.379]
(c) 2018 Microsoft Corporation. Tous droits réservés.

C:\Users\Laurent>set OPENCV_IO_MAX_IMAGE_PIXELS=50000

C:\Users\Laurent>"f:\Program Files\Python\python.exe"
Python 3.6.6 (v3.6.6:4cf1f54eb7, Jun 27 2018, 03:37:03) [MSC v.1900 64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> import cv2 as cv
>>> cv.imread("g:/lib/opencv/samples/data/lena.jpg")
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
cv2.error: OpenCV(4.1.0-pre) G:\Lib\opencv\modules\imgcodecs\src\loadsave.cpp:75: error: (-215:Assertion failed) pixels <= CV_IO_MAX_IMAGE_PIXELS in function 'cv::validateInputImageSize'

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