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Python faster pixel access

asked 2017-12-20 15:55:30 -0600

1170 ●4 ●18

I'm using a double for loop to iterate over an image, and it's very slow:

for j in range(0, hsv_frame.shape[0]):
    for i in range(0, hsv_frame.shape[1]):
        h = frame[j, i, 0]
        s = frame[j, i, 1]
        v = frame[j, i, 2]

Is there any other way to iterate over the image?

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try to avoid per-pixel operations in general. both numpy and opencv are very fast, when you use vectorized functions. the problem is usually more: finding out, if there's something builtin for your case already, and how it is called.

berak ( 2017-12-21 02:11:57 -0600 )edit

I understand parallelization. Thanks for the insight!

sjhalayka ( 2017-12-21 09:21:43 -0600 )edit

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answered 2017-12-21 00:54:25 -0600

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h, s, v = cv2.split(hsv_frame)

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Absoultely!

supra56 ( 2017-12-21 06:04:37 -0600 )edit

you don't even need the split(), numpy has proper "slices". e.g. it could be:

h = [:,:,0]
s = [:,:,1]
v = [:,:,2]

berak ( 2017-12-21 07:53:24 -0600 )edit

1

Thanks for your help guys! I'm just learning Python. I'll try both methods to see what ends up fastest.

sjhalayka ( 2017-12-21 08:46:52 -0600 )edit

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Asked: 2017-12-20 15:55:30 -0600

Seen: 3,174 times

Last updated: Dec 21 '17

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