videowriter: integer division by zero error
I am using the sample code video-write.cpp(included below for convenience) to learn how to use videos with OpenCV.
#include <iostream> // for standard I/O
#include <string> // for strings
#include <opencv2 core="" core.hpp=""> // Basic OpenCV structures (cv::Mat)
#include <opencv2 highgui="" highgui.hpp=""> // Video write
using namespace std;
using namespace cv;
static void help()
{
cout
<< "------------------------------------------------------------------------------" << endl
<< "This program shows how to write video files." << endl
<< "You can extract the R or G or B color channel of the input video." << endl
<< "Usage:" << endl
<< "./video-write inputvideoName [ R | G | B] [Y | N]" << endl
<< "------------------------------------------------------------------------------" << endl
<< endl;
}
int main(int argc, char *argv[])
{
help();
if (argc != 4)
{
cout << "Not enough parameters" << endl;
return -1;
}
const string source = argv[1]; // the source file name
const bool askOutputType = argv[3][0] =='Y'; // If false it will use the inputs codec type
VideoCapture inputVideo(source); // Open input
if (!inputVideo.isOpened())
{
cout << "Could not open the input video: " << source << endl;
return -1;
}
string::size_type pAt = source.find_last_of('.'); // Find extension point
const string NAME = source.substr(0, pAt) + argv[2][0] + ".avi"; // Form the new name with container
int ex = static_cast<int>(inputVideo.get(CV_CAP_PROP_FOURCC)); // Get Codec Type- Int form
// Transform from int to char via Bitwise operators
char EXT[] = {(char)(ex & 0XFF) , (char)((ex & 0XFF00) >> 8),(char)((ex & 0XFF0000) >> 16),(char)((ex & 0XFF000000) >> 24), 0};
Size S = Size((int) inputVideo.get(CV_CAP_PROP_FRAME_WIDTH), // Acquire input size
(int) inputVideo.get(CV_CAP_PROP_FRAME_HEIGHT));
VideoWriter outputVideo; // Open the output
if (askOutputType)
outputVideo.open(NAME, ex=-1, inputVideo.get(CV_CAP_PROP_FPS), S, true);
else
outputVideo.open(NAME, ex, inputVideo.get(CV_CAP_PROP_FPS), S, true);
if (!outputVideo.isOpened())
{
cout << "Could not open the output video for write: " << source << endl;
return -1;
}
cout << "Input frame resolution: Width=" << S.width << " Height=" << S.height
<< " of nr#: " << inputVideo.get(CV_CAP_PROP_FRAME_COUNT) << endl;
cout << "Input codec type: " << EXT << endl;
int channel = 2; // Select the channel to save
switch(argv[2][0])
{
case 'R' : channel = 2; break;
case 'G' : channel = 1; break;
case 'B' : channel = 0; break;
}
Mat src, res;
vector<mat> spl;
for(;;) //Show the image captured in the window and repeat
{
inputVideo >> src; // read
if (src.empty()) break; // check if at end
split(src, spl); // process - extract only the correct channel
for (int i =0; i < 3; ++i)
if (i != channel)
spl[i] = Mat::zeros(S, spl[0].type());
merge(spl, res);
//outputVideo.write(res); //save or
outputVideo << res;
}
cout << "Finished writing" << endl;
return 0;
}
However, once the program starts to write to the output file, 3 lines from the bottom of the code, I get the error below. I get the same error using either output method, and if I try to just put the src straight back to the output(outputVideo << src).
I found another sample program(http://opencv.willowgarage.com/wiki/documentation/cpp/highgui/VideoWriter) that opens the default camera(my built-in webcam), it is able to output just fine. This code is below.
#include "opencv\cv.h"
#include "opencv\highgui.h"
using namespace cv;
int main(int, char**)
{
VideoCapture capture(1); // open the default camera
if ...