Bazze's profile - activity

Hmm okey. I'm not sure if OpenCV even supports windows XP, but make sure you meet these prerequisites: http://en.wikipedia.org/wiki/OpenCV#Windows_prerequisites

You need to upgrade to Windows Vista or higher. See this thread: http://www.dayzcc.tk/index.php?page=Thread&threadID=3322

It should do it.

After a google search I found suggestions on that you might be running an old Windows version? XP maybe? Or an old version of the .NET framework? (Source: http://www.dayzcc.tk/index.php?page=Thread&threadID=3322) EDIT: Ah you wrote you were running XP, so you should probably upgrade to XP. I'll add it as an answer.

Hello!

I need to convert two points, (x1,y1) and (x2,y2), to rho and theta. What is the simplest way to do that?

This is my try so far and I'm not sure if it's correct:

cv::Vec2f LineProcessor::pointsToRhoTheta(double x1,double x2,double y1,double y2){

   double cvTheta=0;
   double cvRho=0;
   double k=0;
   if (x2-x1!=0) {
      k=(y2-y1)/(x2-x1);
   } else {
      k=99999;
   }

   double xSlope,ySlope,m;
   m=y1-k*x1;

   xSlope=-m/(k+(1/k));
   ySlope=m/(pow(k,2)+1);

   if (std::atan2((ySlope),(xSlope))<0) {
      cvTheta=std::atan2((ySlope),(xSlope))+CV_PI;
      cvRho=-std::sqrt(pow(xSlope,2)+pow(ySlope,2));
   } else {
      cvTheta=std::atan2((ySlope),(xSlope));
      cvRho=std::sqrt(pow(xSlope,2)+pow(ySlope,2));
   }

   cv::Vec2f lineRhoTheta;

   lineRhoTheta[0]=cvRho;
   lineRhoTheta[1]=cvTheta;

   return lineRhoTheta;
}

Has anyone done this before?