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modify pixel of image with 0.01

asked 2014-11-13 04:21:40 -0500

Deepak Kumar gravatar image

updated 2014-11-14 03:52:31 -0500

hi, i have a image i want to modify it each pixel of image having 0 value with 0.01. below is the code to replace the value 0 with 0.01. but it is not doing any thing.

code -

for (int y=0; y<contrast.rows; y++)
{
        for (int x=0; x<contrast.cols; x++)
    {
    if(contrast.at<uchar>(y, x) ==0)
            contrast.at<uchar>(y, x) = 0.01;
    }
}

thanks

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Comments

Google unsigned char.

boaz001 gravatar imageboaz001 ( 2014-11-14 04:33:38 -0500 )edit

If your image is of type 8UC1 (thats why I suppose that you are using uchar), its values are integers, not floating point, and is very likely that they are between 0(black) and 255(white). The least value that you can add is 1. Attributing 0.01 to a uchar variable will round it to 0.

R.Saracchini gravatar imageR.Saracchini ( 2014-11-14 04:37:52 -0500 )edit

It's normal, since uchar is an integer type!!!

kbarni gravatar imagekbarni ( 2014-11-14 04:49:57 -0500 )edit

i want to replace 0 value from 0.01. how can i do this?

Deepak Kumar gravatar imageDeepak Kumar ( 2014-11-14 05:33:31 -0500 )edit

of course,it can not convert,because contrast.at<uchar>(y, x) means at point(x,y) the value type is unsigned char, if you want to replace the value from 0 to 0.01, at first, you should convert contrast to double or float type ,for example contrast.at<float>(y,x)=0.01

wuling gravatar imagewuling ( 2014-11-14 06:05:27 -0500 )edit

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answered 2014-11-14 04:14:40 -0500

berak gravatar image

the short answer is: you can't.

the longer one: a uchar Mat holds integer values, 0,1,2,3,...255. so assigning 0.01 will lead to rounding to the nearest integer, 0.

a value of 0.01 would probably only make sense for a float image in the [0..1] range, so:

Mat contrast = ... // CV_8U
Mat contrast_f;
contrast.convertTo( contrast_f, CV_32F, 1.0/255);

for (int y=0; y<contrast_f.rows; y++)
{
    for (int x=0; x<contrast_f.cols; x++)
    {
        if(contrast_f.at<float>(y, x) ==0)
            contrast_f.at<float>(y, x) = 0.01f;
    }
}

if you still want to keep your uchar contrast image, the smallest non-0 value you can assign is 1 (while the largest is 255).

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Asked: 2014-11-13 04:21:40 -0500

Seen: 151 times

Last updated: Nov 14 '14