2017-06-30 14:14:42 -0600 | commented question | Output of DFT is the same as input yes we are |
2017-06-30 14:00:37 -0600 | commented question | Output of DFT is the same as input Ok, so what we are trying to accomplish is:
And since we're stuck in point #3 and have no idea how to use dft() we decided to play with the function on the smallest possible data - a single point. However we're disappointed with the results returned. |
2017-06-30 13:01:54 -0600 | commented question | Output of DFT is the same as input I'm working with OP to solve this problem, we're both new to image analysis and the documentation is quite complicated. How should the dft() function be called if we want to calculate DFT for a single point of the image contour? I was expecting that converting both coordinates into a single complex number should be enough to pass it into dft() and get a fourier descriptor - a single value in output matrix. But probably my way of thinking is incorrect. |