Ztar03's profile - activity

How to get the length of each of the curves present in the image? I have an image of a retina, I need to calculate the l

How to get the length of each of the curves present in the image? I have an image of a retina, I need to calculate the l

Thank you very much for the help you've resolved by adjusting the angle at which the Hough works and have gone a little further segmentation only now emerged a new problem I hope you can help me here I leave the link http://answers.opencv.org/question/53...

Hi all Yesterday I posted a question which fortunately resolved I'm just now another problem, what is at issue is this ... since I submitted my images to different algorithms ... get a picture with rail lines but are not complete ... I was finding out the equation of each line and solve the system of equations ... and I have a program that gives me the coordinates of the intersection but now my problem is to keep the coordenas delivering HoughP to solving the system of equations and thus finally draw the lines to form a kind of triangle.

Enclose the images obtained

This is what I try to do ...

This is the code of the intersection

 #include <iostream>
 #include <vector>
 #include <stdio.h>
 #include <iomanip>
 #include <iostream>
 #include <math.h>
 #include <algorithm>

 using namespace std;
 int main(){
 float x1 = 406;
 float x2 = 436;
 float x3 = 202;
 float x4 = 206;
 float y1 = 83;
 float y2 = 93;
 float y3 = 7;
 float y4 = 100;

 float d = (x1 - x2) * (y3 - y4) - (y1 - y2) * (x3 - x4);
// If d is zero, there is no intersection
 if (d == 0) {
    cout << "NO hay interseccion\n";
 }

 // Get the x and y
 float pre = (x1*y2 - y1*x2);
 float post = (x3*y4 - y3*x4);
 float x = ( pre * (x3 - x4) - (x1 - x2) * post ) / d;
 float y = ( pre * (y3 - y4) - (y1 - y2) * post ) / d;

// Check if the x and y coordinates are within both lines
if ( x < min(x1, x2) || x > max(x1, x2) || x < min(x3, x4) || x > max(x3, x4) ){
    cout << "son colineales\n";
} 
if ( y < min(y1, y2) || y > max(y1, y2) || y < min(y3, y4) || y > max(y3, y4) ) {
    cout << "son colineales\n"; 
}

// Return the point of intersection
cout << x << "\n";
cout << y << "\n";
return 0;

}

And this is the part that takes the HoughP and trace the lines

  vector<cv::Vec4i> findLines(cv::Mat& binary) {
       lines.clear();
       cv::HoughLinesP(binary, lines, 1, CV_PI/720, 25, 10, 10 );
      return lines;
  }
  // Draw the detected lines on an image
  void drawDetectedLines(cv::Mat &image, cv::Scalar color=cv::Scalar(255,0,0)) {
         // Draw the lines
          vector<cv::Vec4i>::const_iterator it2= lines.begin();
          while (it2!=lines.end()) {
          float x1=((*it2)[0]);
          float y1=((*it2)[1]+shift);
          float x2=((*it2)[2]);
          float y2=((*it2)[3]+shift);
          cv::Point pt1(x1,y1);        
          cv::Point pt2(x2,y2);
          //Angle lines
          double Angle = atan2(pt2.y - pt1.y,pt2.x - pt1.x) * 180.0 / CV_PI; 
          if(Angle>10){
                cv::line( image, pt1, pt2, color, 6 );
                cout << "Angulo "<< Angle << "\n"; 
           } 

              cout << " HoughP line: ("<< pt1 <<"," << pt2 << ")\n"; 
                      ++it2;
          }

  }

I made an algorithm which detect the Hough lines present in the image after that make a bitwise between the lines obtained in Hough and HoughP and get a picture like that enclose, now what I need is to join the lines to form a triangle,someone to suggest something ??

Hello good evening I started researching about getting the ROI of an image and from what I understand is using function RECT I've tried but I get an error and honestly do not quite understand its parameters mean, if someone can help me roi get the picture attached below.

My code is the next

Mat image;
image = imread(argv[1]);
int alto = 100; 
Rect roi(0,(image.rows)-alto,image.cols,alto);
Mat imgROI = image(roi);
imwrite("ROI.jpg",imgROI);

and the error is the next

Sizes of input arguments do not match (The operation is neither 'array op array' (where arrays have the same size and type), nor 'array op scalar', nor 'scalar op array') in binary_op, file /home/jenny/Downloads/opencv-2.4.9/modules/core/src/arithm.cpp, line 1021 terminate called after throwing an instance of 'cv::Exception'

I modified the code as you indicated to me and now I got a picture like the one attached.

I am working with the same and have some problems someone to provide me ideas because even though I try not detect the dotted lines lane and sometimes yellow either http://answers.opencv.org/question/53...