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c++, the scope of play Window, cv::namedWindow() and cv::imshow()

What is the scope of created Window? For example:

void play_function(){
    cv::imshow("display", image data);
}

int main(){
    cv::namedWindow("display", 1)
    for(int i=0; i<10; i++){
        play_function()
    }
}

Since the window "display" in play_function() is not in the scope of initialized "display" in main() as normal scope scheme of general variables, I am not sure the Window "display" are the same one as in main()?

The reason I ask this is that I found out that the first time when calling cv::imshow in play_function, it takes tremendous time, so I am wondering if Window "display" did the initialization again in play_function(). Thanks a lot.

c++, the scope of play Window, cv::namedWindow() and cv::imshow()

What is the scope of created Window? For example:

void play_function(){
    cv::imshow("display", image data);
}

int main(){
    cv::namedWindow("display", 1)
    for(int i=0; i<10; i++){
        play_function()
    }
}