FindHomography

findHomography

asked 2015-02-01 22:47:59 -0600

I have some difficulties with very simple use of FindHomography. This is my simple code.

std::vector<cv::Point2f> P1(3);
P1[0].x = 10;  P1[0].y = 10;
P1[1].x = 20;  P1[1].y = 20;
P1[2].x = 30;  P1[2].y = 30;

std::vector<cv::Point2f> P2(3);
P2[0].x = 210; P2[0].y = 210;
P2[1].x = 220; P2[1].y = 220;
P2[2].x = 230; P2[2].y = 230;

cv::Mat T;
T = cv::findHomography( mat_p1, mat_p2, 0 );

The result matrix is

[-1.#IND, -1.#IND, -1.#IND; 1.#INF, -1.#INF, -1.#IND; -1.#IND, -1.#IND, -1.#IND]

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answered 2015-02-02 03:48:43 -0600

Michael Burdinov
4638 ●6 ●33 ●86

updated 2015-02-02 09:14:16 -0600

FindHomography need to calculate perspective transform. Perspective transform has 8 parameters. This means that it requires at least 8 equations to get single solution. In other words you need to provide at least 4 pairs of points to FindHomography.

Edit: Just having 4 pairs of points is not enough. System of 8 equations with 8 unknown variables can't be solved if there linear dependence between equations. The points you used are on the same line. This create linear dependence and makes the system unsolvable. You should not use co-linear segments.

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you are right it needs more 4 or more pairs of points and OpenCV send assert if it os <4. I did a wrong cut/paste operation for creating my message. The right code is this one

std::vector<cv::Point2f> P1(4);
P1[0].x = 10;  P1[0].y = 10;
P1[1].x = 20;  P1[1].y = 20;
P1[2].x = 30;  P1[2].y = 30;
P1[3].x = 40;  P1[3].y = 40;

std::vector<cv::Point2f> P2(4);
P2[0].x = 210; P2[0].y = 210;
P2[1].x = 220; P2[1].y = 220;
P2[2].x = 230; P2[2].y = 230;
P2[3].x = 240; P2[3].y = 240;

cv::Mat T;
T = cv::findHomography( P1, P2, 0 );

I have also tried with 10 pairs of points with the same result.