Read an image with imread() [closed]

asked 2014-03-10 14:11:37 -0500

residentelvio gravatar image

updated 2014-03-11 04:06:04 -0500

berak gravatar image

Hi people, I have this part of code and I d like to undrestand better it.

  Mat img=imread(".....");   //... is a path


    cerr <<" Error message:" << argv[1];
    return 1;

  if (img.empty(){
    cout << "the image is empty\n";
    return -1;

First line load an image by passing directly the path of the image. After it load an image if is passed by command line, as cmd, or terminal. Can I understand better how. Why is it used argv[1]? Is it a need to use 2 time the control about if the imafe is loaded? I understand is a control firstly for the second kind of loading image and after for the 1st (load by adding path)

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Closed for the following reason the question is answered, right answer was accepted by sturkmen
close date 2020-08-16 13:12:50.724041


First, what are you trying to accomplish, what is the goal you are trying to achieve?

Will Stewart gravatar imageWill Stewart ( 2014-03-10 15:07:18 -0500 )edit

Load an image by passing the path or by a command line interface (I don t know if the right term in English) . Howewer the code works.I just want to understand better why is used in that way. How is used about the command line loading in that way

residentelvio gravatar imageresidentelvio ( 2014-03-11 06:35:00 -0500 )edit

I mean why argv[1] is the path of an image passed by command line?

residentelvio gravatar imageresidentelvio ( 2014-03-11 06:37:22 -0500 )edit

This seems more like a C/C++ question than an OpenCV question. You need to figure out about argv.

unxnut gravatar imageunxnut ( 2014-03-11 07:04:49 -0500 )edit

Yes, argv[1] is the first command line parameter.

GilLevi gravatar imageGilLevi ( 2014-03-11 08:52:39 -0500 )edit