Dear All, i have image info in Z matrix, say cv:Mat Z;
If i use x, y index to access the data in the unsigned char data matrix inside Z, how can I access the green channel data value only for that particular x, y index. I like to implement most efficient way in terms of processing speed. Thanks, Thomas
There are great tutorials in the OpenCV documentation. Just have a look at the available tutorials for the core module. The Core Functionality. You want to read:
HI ALL. Thanks for the suggestions. But according to this tutorial http://docs.opencv.org/trunk/doc/tutorials/ios/video_processing/video_processing.html#opencviosvideoprocessing If I set self.videoCamera.grayscale = NO; data output will be 32 bit BGRA. So i still need to skip 1 byte data. Thanks
Do you keep your images in BGRA format?
This might help.
Mat img = imread("filename.jpg",CV_LOAD_IMAGE_COLOR);
unsigned char *input = (unsigned char*)(img.data);
int i,j,r,g,b;
for(int i = 0;i < img.cols;i++){
for(int j = 0;j < img.rows;j++){
b = input[img.cols * j + i ] ;
g = input[img.cols * j + i + 1];
r = input[img.cols * j + i + 2];
}
}Here, g will give the green color for Row - i, Column -j . For more info Read this.
There 2 issues with correcteness of this code and 2 issues with performance. Correctness 1: instead of 'i' there should be '3 * i', because every pixel takes 3 bytes. Correctness 2: instead of 'img.cols * j' there should be 'img.step * j', because offset between 2 rows is at least 3 * img.cols (and may be more if this is ROI of bigger image). Performance 1: order of 'for' loops should be reversed, because Mat stored in row major order not column major. So scaning it column by column incurs huge penalty on memory access, especially for big images. Performance 2: proper order of loops also reduce amount of computaton needed per pixel. To conclude all this: see tutorial mentioned by Philipp for correct way of accessing pixels.
Oh! Thanks for that. I guess I have been doing it all wrong. Should I delete the answer?
I don't know. Remove it if you wish. On one hand it will keep answers cleaner, but on other hand negative answer is also an answer.
If you're using gray images, you need to change.'Cause you don't have three channels.
cout<<(int)input[lung_left.step * j + i];
I don't understand why do i have bad score. I wanted to help.
Asked: Sep 22 '12
Seen: 11,633 times
Last updated: Nov 22 '15
