measure a curved petiole
Hello I want to measure the length of a bramble petiole so there are spines and it is often curved. Ideas please ? Thank you :) Bye
Hi I am trying to extract the petiole of a leaf even if it is very small andif there are tooth on the leaf. An idea ? Thank you :) Bye
Hi I am trying to extract the midrib of a leaf Here is my code :
int main( int argc, char** argv )
{
src = imread( "foliole1.jpg" , IMREAD_COLOR ); // Load an image
Mat drawing = src.clone();
Mat bgr[3]; //destination array
split(src,bgr);//split source
src_gray=bgr[1];//green channel
imwrite("gray.bmp",src_gray);
Mat grayBlurred;
blur( src_gray, grayBlurred, Size(4,4) );
Mat detected_edges_canny;
Canny( grayBlurred, detected_edges_canny,50,100,3);
imwrite("grayBlurred.jpg",grayBlurred);
imwrite("detected_edges_canny.jpg",detected_edges_canny);
vector<Vec4i> lines;
HoughLinesP(detected_edges_canny, lines, 1, CV_PI/360, 30,100, 20);
double maxLength=0;
bool found;
Segment midRib;
Mat segments=src.clone();
for( size_t i = 0; i < lines.size(); i++ )
{
Vec4i l = lines[i];
Segment S=Segment(Point(l[0], l[1]), Point(l[2], l[3]));
S.draw(segments,2,Scalar(0,0,255));
if (S.getLength()>maxLength)
{
midRib=S;
found=true;
maxLength=S.getLength();
}
}
imwrite("segments.jpg",segments);
Mat midrib=src.clone();
midRib.draw(midrib,2,Scalar(0,0,255));
imwrite("midrib.jpg",midrib);
}
and the images are at : http://sylvain-ard.fr/temp/ like you can see it doen't works. please help me thank you :) bye
Hi, for doing several spines measurements I want firstly to extract the contour of the underside of bramble stems. For example for this image : http://www.sylvain-ard.fr/temp/image2... I want the contours in red in this image : http://www.sylvain-ard.fr/temp/image.jpg other examples of stems are : http://www.sylvain-ard.fr/temp/image3... http://www.sylvain-ard.fr/temp/image4... Thank you ! Best regards
You wanna to remove stem?
No to detect them but it's goodI suceeded
You wanna contour on red but not on top or both? Is that right?
yes but I succeeded, thank you
I succeeded
Post result image. Will you?