convert cv::Mat to vector<vector<uchar>> img;

matrix

asked 2020-01-08 02:21:34 -0600

dineshlama
70 ●3 ●6

updated 2020-01-08 02:31:39 -0600

LBerger
9317 ●2 ●20 ●88 http://www.traimaocv.fr

how do i efficiently convert cv::Mat to vector<vector<uchar>> img. right now i am trying beolove code:

vector<vector<Vec3b>> inputImg(OrigImg.cols,vector<Vec3b>(OrigImg.rows));
for(int i=0;i<OrigImg.cols;i++) {
  for(int j=0;j<OrigImg.rows;j++) {
    inputImg[i][j] = backgroundSubImg.at<cv::Vec3b>(j,i);
  }
}

Why i'm trying to do is since it looks like accessing each pixel in cv::Mat or scanning hole image is little bit slower by using backgroundSubImg.at<cv::vec3b>(j,i); i want to access the color values of this pixels only by its position. Right now my algorithm is accessing every pixel 6404608 times in each cycle.

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answered 2020-01-08 09:46:27 -0600

exbigboss
66 ●1 ●3

If your goal is speed, you shouldn't be making a copy. Nor should you be using non-contiguous allocations like a vector of vectors.

Instead, invert this problem. Create a storage vector up-front and then create cv::Mat on top of that.

You want a single flat contiguous allocation for cache coherency and you want to avoid the copy as well.

In essence, just do:

auto storage = std::vector<uchar>(480 * 640 * 3); // or however many channels you have
auto mat     = cv::Mat_<uchar>(480, 640, CV_8UC3, storage.data());

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answered 2020-01-09 02:32:30 -0600

LBerger
9317 ●2 ●20 ●88 http://www.traimaocv.fr

You can try :

    Mat a(6, 6, CV_8UC3, Scalar(1, 64, 192));
    vector<vector<uchar>> v(a.rows);
    for (int i = 0; i < a.rows; i++)
    {
        a.row(i).reshape(1,1).copyTo(v[i]);
    }
    for (int i = 0; i < a.rows; i++)
    {
        for (auto j : v[i])
            cout << int(j) << "\t";
        cout << "\n";
    }

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answered 2020-01-08 16:04:58 -0600

sjhalayka

1170 ●4 ●18

Using a 2D vector like this is not as efficient as using a single vector<uchar> to hold all of the pixels, where the index is equal to size_t index = y*x_resolution+x; Here y and x are gotten from for loop iteration.

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convert cv::Mat to vector<vector<uchar>> img;

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