Log Polar Transform
I have been going through the latest OpenCV implementation of the Log Polar Transform using the Blind Spot Model. I am a bit confused as to how the cortical image size (sectors x rings) is being calculated. The inputs I provide are width & height of original image, center point, rings, blindspot size and I ask OpenCV to internally calculate the sectors.
Given this, my cortical image size turns out to be 120 x 134 when I give the following values as inputs : width = 800, height = 600, center(400,300), rings R = 120, blindspot size ro0 = 1, romax = 0.5*min(width,height). This means that my no of sectors is being internally calculated to be 134 to keep the aspect ratio of the log-polar template = 1.
If I manually calculate S = 2pi/(a-1) where a = exp(ln(romax/ro0)/R) I however get S = 130
I am not sure why I am getting this discrepancy of 4 rows. Any suggestions would be helpful.
Thanks
