Video from IP camera can't find starting number cv::icvExtractPattern

edit

I use openCV on windows 10 and I sharing an image from android via ip address.

I need to see the code for c++ and python for CAP_IMAGES I don't want to entire code. Just a single code.

This code it`s build in opencv 4.1.1 and it's works, but in 3.4.7 not.

#include <opencv2/opencv.hpp>
using namespace cv;
using namespace std;
int main()
{
    Mat image, dst;
    cv::VideoCapture vcap;
    const std::string videoStreamAddress = "http://192.168.1.109:8080/video";

    if (!vcap.open(videoStreamAddress))
    {
        std::cout << "Error opening video stream or file" << std::endl;
        return -1;
    }
    else {
        cout << "Open." << endl;
    }
    while (vcap.isOpened()) {
        vcap >> image;
        resize(image, dst, cv::Size(640, 320));
        imshow("Input", dst);
        waitKey(1);
    }
}

Python is almost the same:

import cv2

cap = cv2.VideoCapture('http://@192.168.1.109:8080/video')
while(True):

    ret, frame = cap.read()
    cv2.imshow('frame',frame)

    if cv2.waitKey(1) & 0xFF == ord('q'):
        break

cap.release()
cv2.destroyAllWindows()

Don't use port and add some extension.

const std::string videoStreamAddress = "http://192.168.1.109:8080/video";

to:

const std::string videoStreamAddress = "http://192.168.1.109/video.cgi?.mjpg";

Connection via http doesn't work. I was able to run camera only with rtsp protocol.

const std::string videoStreamAddress = "rtsp://192.168.1.109:8080/h264_ulaw.sdp";

Addisionaly when I try give address without specifying the port, opencv set default 80.