How do I can create a Gaussian filter in CUDA that is larger than 32 and double type?

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Thank you. So, if want to apply the filter size larger than 32 x 32 and want high efficiency, I have to write my own custom kernel for that? Now, I am using the `cv::cuda::Convolution::convolution()for that. I don't know it has the same results or not.

You can generate you kernel defining the own choice sigma and apply to the whole image. There is an online calculator, if you know prior the size and the sigma I suppose it could help you in speed up the process. You can find it here.

Try this:

cv::Mat kernel = (cv::Mat(33,33,CV_64F) << /*here the value that you got from the website*/);
cv::Mat result;
cv::Ptr<cuda::Convolution> conv= cuda::createConvolution(Size(33, 33));
conv->convolve(img, kernel, result);

Instead of feed the kernel matrix by hand is possible to create a function to compute it. I found a code in the past but I'm not able to find it again, I'm sorry. By the way, hope it helped.

I have generated the Gaussian kernels (using function) by myself and I add padding to image by using copyMakeBorder and convolve with the generated kernels. But the result is different and get unintended results. New question. I asked the new question in this link. And one more thing, is that cuda::Convolution only accept double type?

Ok, I'll check the new question the next days since I'm a little bit busy till wednesday. Regarding the type, check the documentation according to your OpenCV version. For mine, it says:

image   Source image. Only CV_32FC1 images are supported for now.
templ   Template image. The size is not greater than the image size. The type is the same as image.

So, only float are accepted in the CUDA implementation (CV_32FC1). My fault, you need to change the code I supplied before to use float instead of double.

@HYPEREGO Thank you for your time. It was the same as mine.