histogram opencv c++ vs python

Sky31
13 ●1 ●3

updated 2019-01-01 03:39:38 -0600

I'm converting histogram function which is written in c++ into python.

    Mat  Detection:: histogram(Mat img,bool vis)
{
    int bins = 59;             // number of bins 256 -1 to ignore the last patterns (background pattern)

    Mat hist;       // histogram arrays
    // Initalize histogram array
    hist = Mat::zeros(bins, 1, CV_32FC1);
    for (int i = 0; i < img.rows; i++)
    {
        for (int j = 0; j < img.cols; j++)
        {
                uchar val =img.at<uchar>(i,j);
                hist.at<float>(lookup[val]) += 1;   #on this line I'm facing the problem(is it talking about the lookup table? )
        }
    }

    return hist;
}

python conversion

def historgram(image):
    #cv2.historgram()
    bins = 59
    row,col,channels = image.shape

    hist = np.zeros((bins, 1), dtype = 'float32')    
    i = 0 
    j =0 
    while i < row:
        while j < col:
            val = image[i,j]
           ""
                      ""

            j = j+1
        i = 1+i
    return hist

How should I do the conversion in python of this part [hist.at<float>(lookup[val]) += 1]?

Thankyou

Comments

how would we know, without any context ?

berak ( 2019-01-01 03:22:31 -0600 )edit

I just updated the code Kindly look into it

Sky31 ( 2019-01-01 03:29:44 -0600 )edit

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answered 2019-01-01 04:12:41 -0600

berak
32993 ●7 ●81 ●312

updated 2019-01-01 04:15:39 -0600

since this looks like the "uniform lbp" lookup, there should have been a table / array, like this:

lookup = [   # the well known original uniform2 pattern
    0,1,2,3,4,58,5,6,7,58,58,58,8,58,9,10,11,58,58,58,58,58,58,58,12,58,58,58,13,58,
    14,15,16,58,58,58,58,58,58,58,58,58,58,58,58,58,58,58,17,58,58,58,58,58,58,58,18,
    58,58,58,19,58,20,21,22,58,58,58,58,58,58,58,58,58,58,58,58,58,58,58,58,58,58,58,
    58,58,58,58,58,58,58,58,58,58,58,58,23,58,58,58,58,58,58,58,58,58,58,58,58,58,
    58,58,24,58,58,58,58,58,58,58,25,58,58,58,26,58,27,28,29,30,58,31,58,58,58,32,58,
    58,58,58,58,58,58,33,58,58,58,58,58,58,58,58,58,58,58,58,58,58,58,34,58,58,58,58,
    58,58,58,58,58,58,58,58,58,58,58,58,58,58,58,58,58,58,58,58,58,58,58,58,58,58,
    58,35,36,37,58,38,58,58,58,39,58,58,58,58,58,58,58,40,58,58,58,58,58,58,58,58,58,
    58,58,58,58,58,58,41,42,43,58,44,58,58,58,45,58,58,58,58,58,58,58,46,47,48,58,49,
    58,58,58,50,51,52,58,53,54,55,56,57]

think of it as some kind of "compression", going from [0..255] values to [0..58].

then inside your loops, you can use it like:

val = image[i,j]
hist[lookup[val]] += 1

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Comments

Thanks a lot :)

Sky31 ( 2019-01-01 04:58:16 -0600 )edit

@Sky31 please mark the answer as correct.

sturkmen ( 2019-01-01 07:53:44 -0600 )edit

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histogram opencv c++ vs python

python conversion

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histogram opencv c++ vs python