Sobel automatically default to Scharr when kernel size == 3?

Martian
151 ●4 ●11

From the OpenCV docs:

Sobel is only an approximation of the derivative). OpenCV addresses this inaccuracy for kernels of size 3 by using the Scharr() function.

Does this mean that calling "Sobel()" with a kernel size of 3 will actually call the Scharr() function internally?

2 answers

berak
32993 ●7 ●81 ●312

so, the answer is:

NO.

IF you want to use the Scharr kernel, specify -1 for the ksize param. else a Sobel kernel of size k is used.

Why two answers ? I can read only one

LBerger ( 2018-09-12 01:20:57 -0600 )edit

^^ bug, i'd say. if ppl remove an answer, counter does not decrement

berak ( 2018-09-12 01:22:44 -0600 )edit

There is duplicate post list but in @Martian question there is three questions : bug and bug

LBerger ( 2018-09-12 01:36:46 -0600 )edit

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Asked: 2018-09-09 04:21:55 -0600

Seen: 210 times

Last updated: Sep 11 '18