How to drawContours with gradient colors, not with single color.
cv::drawContours( img, contours, i, color, CV_FILLED, 8, std::vector<cv::vec4i>(), 0, cv::Point() );
As drawContours require a single color, So my question is how to pass a gradient instead of single color.
You have to do it manually. Use the LineIterator to draw lines algorithmically; you can change the color of each pixel.
Then you have to iterate the lines that form the polygon of a contour and through the different contours.
Here is the pseudocode of the algorithm. It's almost ready, but it isn't tested, so you'll have to finish it and adapt it to your needs.
for(int k=0;k<contours.size();k++){
contour = contours[k]; //the current contour
for(int l=0;l<contour.size();l++){
p0=contour[l];p1=contour[(l+1)%contour.size()]; //the endpoints of the line
//the last line will be between the last and first points, that's why the % operator
LineIterator it(img, p0, p1, 8); //this will generate the list of points on the line.
for(int i=0; i<it.count; i++)
{
Vec3b(*it)=nextColor(); //it's up to you to generate the gradient as you like
it++;
}
}
}
It's just a function to generate the color of the next pixel. It depends what kind of gradient you want. You might also generate a look-up table (LUT) to get the next color.
For a grayscale (and one channel) gradient, it is:
uchar color=0;
uchar nextColor() { return (color++)%256; }
You can also imagine a gradient dependent on the Y parameter of the pixel, and so on...
Asked: 2018-07-18 05:54:48 -0600
Seen: 2,655 times
Last updated: Jul 18 '18
there is no such thing builtin.