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2 dim matrix, how can it be

asked 2018-01-23 18:16:25 -0500

julian403 gravatar image

Hello. I hope you all are fine.

Im new with this API and as every newbie I need a little help here. I'm using a banana pi m2 and a usb cam (a genius one). First of all I want to check the camera paramters, so:

    #include <stdio.h>
#include <opencv2/opencv.hpp>
#include <opencv2/highgui.hpp>

using namespace cv;
using namespace std;

int main(int argc,char ** argv)
{
  VideoCapture cap(0);
  if (!cap.isOpened()) {
    cerr << "ERROR: Unable to open the camera" << endl;
    return 0;
  }
  Mat frame1, frame;
  cout << "Start grabbing, press a key on Live window to terminate" << endl;

        cap >> frame1;
        if (frame1.empty())
                {
                cerr << "ERROR: Unable to grab from the"<<endl;
                }
        int i, j, k,z;
i=frame1.dims;
j=frame1.cols;
k=frame1.rows;
z=frame1.type();

        printf("%d dim\n  %d col \n  %d row\n %d type\n", i, j, k, z);

return 1;
}

And this is what a I got:

Start grabbing, press a key on Live window to terminate
2 dim
640 col
480 row
16 type

How can be a matrix 2 dimension??? So, thats means that it has just 2 colors? its a two channel?

Also, a 16 type means CV_8U. So there is 8 bits per color(R G or B)? because VGA use 6bits per color Thanks in advance.

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Comments

the dimension you're missing is in frame.channels() (3) and it is BGR ordered

(but it is not really a "dimension", since the pixels are interleaved)

berak gravatar imageberak ( 2018-01-24 00:21:22 -0500 )edit

Thanks.

But, what do you means when you said "the pixels are interleaved"? Thats ones question that I still have because there is 8bits per color (RGB) on CV_8U and every matrix element (pixel) has 32 bits?? and thats pixel with RGB color are consecutive?

julian403 gravatar imagejulian403 ( 2018-01-24 08:55:55 -0500 )edit

again it is BGR, not RGB in opencv (and also numpy). like b g r b g r b g r .... (so yes, consecutive, not in seperate color planes (like it is in matlab)

also, that would make 24bits per pixel, not 32 (alpha has no real use in computer-vision)

berak gravatar imageberak ( 2018-01-24 09:05:37 -0500 )edit

Thanks a lot and the last one:

So if CV_8U has a deep pixel of 24bits that implies that CV_32F has 96 bits?

julian403 gravatar imagejulian403 ( 2018-01-24 09:27:57 -0500 )edit

CV_8U == a single channel (grayscale, 8 bit image)

CV_8UC3 == 3 8bit channels (bgr, hsv, yuv, etc.)

CV_32F == a single channel 32bit float image

CV_32FC3 == 3 32bit float channels

CV_64FC2 == .... you'll get the picture, i hope ..

berak gravatar imageberak ( 2018-01-24 09:31:32 -0500 )edit

But

CV_32FC3 == 3 32bit float channels. There is 32 bits per color (B G R) and thats 96 bits deep pixel which gives 2^96 total color. For what I know the human can see 2^24 color and the alpha is just the transparency. Its not too much 96 bits? for what I know all camera works with 32 bits including alpha.

julian403 gravatar imagejulian403 ( 2018-01-24 09:36:48 -0500 )edit

"There is 32 bits per color (B G R) and thats 96 bits deep pixel" -- exactly.

" For what I know the human can see 2^24 color " -- this is computer-vision , humans don't count ;)

also, there are a lot of Mat's that do not contain images per se, like transformations, neural network layers, distance tables, and whatnot.

" for what I know all camera works with 32 bits including alpha." -- no. cameras do not know anything about alpha. (and again, alpha is almost never used here)

berak gravatar imageberak ( 2018-01-24 09:45:34 -0500 )edit

Thank you very much.

julian403 gravatar imagejulian403 ( 2018-01-24 12:17:34 -0500 )edit

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answered 2018-01-24 08:11:01 -0500

Soarez gravatar image

Can you see the image? probably you have a monochromatic image in gray scale. Dim = 2, means that you dont have a x,y matrix with 1 channel .

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Yes I can see the image and its colored

julian403 gravatar imagejulian403 ( 2018-01-24 08:56:58 -0500 )edit
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Asked: 2018-01-23 18:16:25 -0500

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Last updated: Jan 24 '18