#include <iostream>
using namespace std;
int main(int argc, char** argv)
{
CvPoint2D32f test = cvPoint2D32f(12,12);
cout << test << endl;
system("pause");
}
Anyone know why I can't cout test in my code above? And what's the difference between defining test as above and defining it like CvPoint2D32f test = new CvPoint2D32f[144]? Thanks.
You must to use c++ version
CvPoint2D32f test = cvPoint2D32f(12,12);
cv::Point2f testCpp(test);
std::cout << testCPP << std::endl;
Agreed, drop the C-style API, it gets you more errors than you can imagine :)
All parts of your code, containing the Cv caption in front of the function name, says that you are using old OpenCV 1.x C-style types. They have been changed to corresponding C++ style types like illustrated above.
How can I do the same with a matrix (say, ouputting the identity matrix [1 0 0; 0 1 0; 0 0 1] on the screen.) Using the method above doesn't work:
CvMat* test = cvCreateMat(3,3,CV_32FC1); //empty matrix
cv::Mat2f testx(*test);
cout << testx << endl;
And regarding the C-style API, are you saying I'm better off doing something like: using namespace cv; waitKey(0);
rather than cvWaitKey(0);?
Just use the Mat operator instead of CvMat, which can be put into cout directly.
please put some effort in reading the docs ... I just pointer you to the Mat class which has an operator called at<type>(x,y) and if you read further, you can even see that there is a Mat_ type which can be adressed by simple using [x,y].
Asked: 2013-07-30 01:14:39 -0600
Seen: 381 times
Last updated: Jul 30 '13
