cv2.linearPolar() TypeError

asked 2017-07-12 10:40:43 -0600

anandvd
16 ●2 ●4

updated 2017-07-12 10:51:28 -0600

I am trying to convert concentric circles into straight lines using linear polar:

circleArr = np.ndarray((512,512), dtype = np.float32)
for i in range(10,600,10):
    cv2.circle(circleArr, (256,256), i-10, np.random.randint(60,500), thickness = 4)

lp = np.ndarray((512,512), dtype=np.float32)
img1 = cv2.linearPolar(circleArr, lp, (256,256), 100, cv2.INTER_LINEAR+cv2.WARP_FILL_OUTLIERS)

I get the following error referring to the last line:

TypeError: a float is required

I am confused because both the input and output array in the linearPolar() function are float type

Opencv3 and python 3.5.1

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I tried making it float, but still getting the same error

anandvd ( 2017-07-12 10:56:46 -0600 )edit

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answered 2017-07-12 11:01:49 -0600

berak
32993 ●7 ●81 ●312

updated 2017-07-12 11:03:04 -0600

if you take a look at the builtin help():

>>> help(cv2.linearPolar)
Help on built-in function linearPolar:

linearPolar(...)
    linearPolar(src, center, maxRadius, flags[, dst]) -> dst

you'll see, that you don't have to supply the result image (so the order of the following args is one-off).

it should be simply:

img1 = cv2.linearPolar(circleArr, (256,256), 100, cv2.INTER_LINEAR+cv2.WARP_FILL_OUTLIERS)

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It works! Thanks! But in the documentation it mentions the destination as a parameter as well

anandvd ( 2017-07-12 11:05:25 -0600 )edit

yes, in c++. python differs a bit, so it''s always a good idea to cross-check with help() !

berak ( 2017-07-12 11:09:09 -0600 )edit

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cv2.linearPolar() TypeError

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