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dft function

asked 2017-05-31 04:51:35 -0600

Philippe gravatar image

I am using the dft function (tried with both real and complex input.... where imaginary part was set to zero). The output of the dft is in a compressed format.

1) how do I convert this into the natural format?

2) is there a way to calculate the dft without this intermediate step?

3) If I use a real signal with a pure tone (e.g. sine wave), I get artifacts in the dft (instead of only that specific frequency, I get perturbations other frequencies also). Is this a known issue?

4) when I do the inverse dft (to get the original signal), the results typically have 2 orders of magnitude more noise than LabView (language similar to Matlab, with its own FFT algorithm), does OpenVC take shortcuts that include rounding of values?

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answered 2017-05-31 09:35:44 -0600

LBerger gravatar image

updated 2017-05-31 11:15:31 -0600

Question 1 and 2 it is written in doc :

Re Y_{0,0} & Re Y_{0,1} & Im Y_{0,1} & Re Y_{0,2} & Im Y_{0,2} & \cdots & Re Y_{0,N/2-1} & Im Y_{0,N/2-1} & Re Y_{0,N/2}

If you don't want this flag use DFT_COMPLEX_OUTPUT

Mat sigX=(Mat_<double>(1,8)<<1,1,0,0,0,0,0,0),fftsigx;
dft(sigX, fftsigx);
cout << "flag=0 : " << fftsigx << "\n";
dft(sigX, fftsigx, DFT_COMPLEX_OUTPUT);
cout << "flag=DFT_COMPLEX_OUTPUT : " << fftsigx << "\n";

flag=0 : [2, 1.707106781186547, -0.7071067811865475, 1, -1, 0.2928932188134524, -0.7071067811865475, 0]

flag=DFT_COMPLEX_OUTPUT : [2, 0, 1.707106781186547, -0.7071067811865475, 1, -1, 0.2928932188134524, -0.7071067811865475, 0, 0, 0.2928932188134524, 0.7071067811865475, 1, 1, 1.707106781186547, 0.7071067811865475]

Question 3 it is well known issue but not in opencv : window effect.

Question 4 : I want to see your code but with this code no problem

dft(fftsigx, sigX, DFT_COMPLEX_OUTPUT+DFT_INVERSE+DFT_SCALE);
cout << "flag=DFT_COMPLEX_OUTPUT+INVERSE : " << sigX << "\n";
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Asked: 2017-05-31 04:51:35 -0600

Seen: 479 times

Last updated: May 31 '17