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formula of gradient direction

asked 2012-08-13 13:05:08 -0500

Papercut gravatar image

updated 2012-08-28 06:08:23 -0500

Kirill Kornyakov gravatar image

Hi I have found a good paper about Upsampling and been trying to understand formula in the paper. Here's a part of it.

image description

Based on the formula in the screen shot,

I have wrote some c++ codes but I am not sure it is right. Would you guys please tell me if I doing in right way? And Please give me some tips about getting Px..

double Ix, Iy, dI, Nx, Px, t;
t = 3;
Ix = getValueAt(&imageBGR, x+1, y, 0) - getValueAt(&imageBGR, x-1, y, 0);
Iy = getValueAt(&imageBGR, x, y+1, 0) - getValueAt(&imageBGR, x, y-1, 0);
if(Ix == 0) Ix = 0.001;
dI = Iy/Ix;

Nx = sqrt( (Ix*Ix) + (Iy*Iy) );
Px = ??
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answered 2012-08-13 14:02:49 -0500

Michael Burdinov gravatar image

updated 2012-08-13 14:03:55 -0500

This is the most common way to calculate gradient and its direction (although not the only one, there plenty of others).

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Comments

And how to calculate gradient in arbitrary direction?

mrgloom gravatar imagemrgloom ( 2012-08-28 06:17:15 -0500 )edit

Calculate direction and magnitude of gradient and then calculate its projection to direction you need. It should be magnitude*square(cos(angle_between_directions))

Michael Burdinov gravatar imageMichael Burdinov ( 2012-08-29 01:01:44 -0500 )edit
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Asked: 2012-08-13 13:05:08 -0500

Seen: 1,063 times

Last updated: Aug 28 '12