I am trying to calibrate my camera (sony alpha 6000 20mm lens) using open CV. In the parameters list, I can find the focal length coefficient as 5192. How can I calculate the corresponding focal length from that ?
You already know the focal lengths is 20mm, but you might want to compare/check calibration results.
In camera matrix the focal lengths fx,fy are expressed in pixel units. To convert focals in World units Fx, Fy you need sensor size in same units using similar triangle
Fx = fx * W /w or Fy = fy * H /h
where:
W: is the sensor width expressed in world units, let's say mmw: is the image width expressed in pixel fx: is the focal length expressed in pixel units (as is in the camera matrix )Your Sony α6000 is 6000x4000pix and sensor size is 23.5 x 15.6mm hence:
Fx = fx * W /w = 5192pix * 23.5mm / 6000pix = 20.33mm
Fy = fy * H /h = 5192pix * 15.6mm / 4000pix = 20.25mm
At the end your calibration looks good
I am trying to solve the same problem but I do not know the camera sensor width (W) nor height (H). The camera I am using is the built-in back camera of the Samsung Galaxy A5 (2015). The only information I found are the focal length (3.69 mm), the focal length 35mm (28mm) and the image resolution is 2448x3264. Is there any way to transform the intrinsic matrix from pixel to world unit using these info? Extracting the ratios W/w and H/h by doing W/w = Fx/fx seems odd to me because I am assuming that Fx=Fy=3.69mm.
To transform from pixel to world you need to know the object distance and orientation too. N pixels can refer to small near object or large far object, rotation of camera axis changes resulting size of same object at same distance
More in general, you need to calculate extrinsic parameter, rotation and translation matrix for the scene you are viewing. You can use some well know markers in the scene you are viewing. See real-world-camera-position-knowing-marker-geometry
Asked: 2017-04-10 23:26:22 -0600
Seen: 18,375 times
Last updated: Apr 11 '17
