How to get first row of np.vstack? midpoint of contour - Python

asked 2017-01-23 06:19:03 -0600

agroms
26 ●2 ●5

Hello,

Im new to OpenCV and Python, and Im trying to meassure the distance of the midpoints of two contours. This is my code so far:

image = cv2.imread('TwoMarkers.jpg')
gray = cv2.cvtColor(image, cv2.COLOR_BGR2GRAY)
ret, thresh = cv2.threshold(gray, 127 , 255, 0)
im2, contours, hierarchy = cv2.findContours(thresh,cv2.RETR_TREE,cv2.CHAIN_APPROX_SIMPLE)
for c in contours:
    # if the contour is not sufficient large, or to small, ignore it
    if cv2.contourArea(c) > 2000:
        continue
    elif cv2.contourArea(c) < 100:
        continue
    M = cv2.moments(c)
    cX = int(M['m10'] /M['m00'])
    cY = int(M['m01'] /M['m00'])
    contourMidpoint= np.vstack([(cX, cY)])

    D = dist.euclidean(contourMidpoint[0], contourMidpoint[1])
    print(D)

How can I get the distance D between the two found values that are stacked? The apporach I tried dident work, and I have no clue how to sepererate the values that are stacked. Any help is much appreciated.

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# step 1, collect centers: centers=[] for c in contours: # if the contour is not sufficient large, or to small, ignore it if cv2.contourArea(c) > 2000: continue elif cv2.contourArea(c) < 100: continue M = cv2.moments(c) cX = int(M['m10'] /M['m00']) cY = int(M['m01'] /M['m00']) centers.append([cx,cy]) # step 2, compare: if len(centers) >=2: dx = centers[0][0] - centers[1][0] dy = centers[0][1] - centers[1][1] D = math.sqrt(dx*dx+dy*dy) print(D)

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This worked, thank you so much :)

agroms ( 2017-01-23 07:42:52 -0600 )edit

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How to get first row of np.vstack? midpoint of contour - Python

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