OpenCV Q&A Forum - RSS feedhttp://answers.opencv.org/questions/OpenCV answersenCopyright <a href="http://www.opencv.org">OpenCV foundation</a>, 2012-2018.Sun, 29 Mar 2020 06:33:36 -0500Inverse Matrix from a Decomposehomographyhttp://answers.opencv.org/question/228224/inverse-matrix-from-a-decomposehomography/I need to obtain the inverse of a rotation matrix I get from decomposehomography() but I'm having some trouble as it looks like the type of the matrix I obtain from that function does not seem to work with .inv(). Here's an example where Prev_rot_matrix is another matrix
int solutions = decomposeHomographyMat(H, cameraMatrix, Rs_decomp, ts_decomp, normals_decomp);
for (int i = 0; i < solutions; i++)
{
if(normals_decomp[i].at<double>(2)>0)
{
aux=FrameVar(Rs_decomp[i], Prev_rot_matrix); /*Prev_rot_matrix has the same structure as Rs_decomp[i]*/
if(aux<Var)
{
Var=aux;
SOL=i;
}
}
}
double FrameVar(Mat Rot_Curr, Mat Rot_Prev)
{
//Previous rotation: Rot_Prev ;
current rotation: Rot_Curr
double NewAngle, OldAngle, aux;
Mat Rot_Curr_vect, Rot_Prev_vect;
Mat VarAngle(cv::Size(1,1), CV_64FC1);
Rodrigues(Rot_Curr, Rot_Curr_vect);
Rot_Prev_vect=Rot_Prev.inv()*Rodrigues(Rot_Prev, Rot_Prev_vect);
...
So when I try to compile it I get:
> ‘cv::MatExpr’ is not derived from
> ‘const cv::Affine3<T>’
> Rot_Prev_vect=Rot_Prev.inv()*Rodrigues(Rot_Prev,
> Rot_Prev_vect);
and a bunch of other errors.
In case that that meant Rot_Prev class does not have .inv(), how can I obtain its inverse matrix? I want to get the previous rotation vector in the new frame coordinatesAquasSun, 29 Mar 2020 06:33:36 -0500http://answers.opencv.org/question/228224/decomposeHomographyMat isn't workinghttp://answers.opencv.org/question/210199/decomposehomographymat-isnt-working/ I used findHomography, then:
int solutions = decomposeHomographyMat (H, K, R, T, N);
But this doesn't work properly. Rotation matrix has only "-nan" values. Homography martix is ok. It has values like:
> 2.44486e-39, 0.0466184, 1.25152e+23
I've tried to use unit matrix instead of homography, but it also didn't work.viohhWed, 13 Mar 2019 03:20:44 -0500http://answers.opencv.org/question/210199/