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 | 1 | initial version |
intersection distance is just summing up the minimum of the 2, so , if you have 2 histograms,
A = [3,5,6]
B = [11,2,5]
their intersection distance is:
min(3,11) + min(5,2) + min(6,5) == 3 + 2 + 5 == 10
| | 2 | No.2 Revision |
intersection distance is just summing up the (per element) minimum of the 2, so , if you have 2 histograms,
A = [3,5,6]
B = [11,2,5]
their intersection distance is:
min(3,11) + min(5,2) + min(6,5) == 3 + 2 + 5 == 10