This forum is disabled, please visit https://forum.opencv.org
 | 1 | initial version |
Hi, the epipolar constrain (as you mentioned) is x2'Fx1=0 where x2' is the coordinate of the point in the second image and x1 is the coordinate of the point in the first image.
If you use the essential matrix the epipolar constrain is X2'EX1=0 where X2' is the normalized coordinate of the point in the second image and X1 is the normalized coordinate of the point in the first image.
You obtain the normalized coordinate with this:
X = inverse(K)*x
That's why I think you are getting a big number using the essential matrix.