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i don't think, you need the geneal solution above, we can simply exploit, that there are max. 2 times 180 in 360, then it's:

Mat mask = angle > 180.0f; subtract(angle, 180.0f, angle, mask);

or , in one line:

subtract(angle, 180.0f, angle, (angle>180.0f));

i don't think, you need the geneal general solution above, we can simply exploit, that there are max. 2 times 180 in 360, then it's:

Mat mask = angle > 180.0f;
subtract(angle, 180.0f, angle, mask);
mask);

subtract(angle, 180.0f, angle, (angle>180.0f));
(angle>180.0f));

i don't think, you need the general solution above, we can simply exploit, that there are max. 2 times 180 in 360, then it's:

Mat mask = angle > 180.0f;
subtract(angle, 180.0f, angle, mask);

or , in one line:

subtract(angle, 180.0f, angle, (angle>180.0f));

angle.forEach([&](float &f, const int *p) {f = fmod(f,180.0f);});