Finding local maximum in grayscale image

asked 2018-09-13 11:46:10 -0600

Machi
1 ●1

Hello,

I'm new to OpenCV and still learning so I'm looking for an as simple as possible solution to my problem.

I have a sample picture that looks like this

grayscaleImage

I want to find the local maximums in the picture using Python and OpenCV and anything else that could possibly be useful. Scikit-image possibly?

I have researched and found people saying that first I need to dilate the image using a 5x5 kernel with a 0 pixel in the middle and then replace every pixel with the maximum of it's neighbors, although I'm not sure how I should do the 2nd part.

Anyone here willing to help out a noob with a noob-friendly answer? :)

answered 2018-09-13 12:38:57 -0600

matman
1001 ●6 ●16

updated 2018-09-13 12:43:42 -0600

dilate is a maximum filter. Just use it with the desired size and form (MORPH_RECT, MORPH_ELLIPSE, or a custom kernel). If you want to fill gaps use morphologyEx with MORPH_CLOSE as op flag.

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Hmm I have tried

result = cv2.dilate(img, cv2.getStructuringElement(cv2.MORPH_RECT,(5,5)))

but I only get this https://i.imgur.com/BIF4Pps.png as the result. It just makes the maximum blobs bigger, I am not sure how to use that for what I need to do.

Machi ( 2018-09-13 14:19:05 -0600 )edit

I don't know exactly what you want. If you try to do a NonMaximumSupression try something like (For C++):

cv::Mat imgMax = dilate(img, getStructuringElement(MORPH_RECT, cv::Size (5, 5));
cv::Mat imgResult.create(img.size(), img.type(), cv::Scalar::all(0));
img.copyTo(imgResult, compare(img, imgMax, CMP_GE);

matman ( 2018-09-15 08:32:53 -0600 )edit

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