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Distance from an object.. Where is the camera origine?

asked 2017-04-13 08:45:43 -0500

ROSpioneer gravatar image

I compute the distance from an object (Chessboard) using OpenCv and my camera parameters using those steps:

findChessboardCorners

solvePnP

->Distance

The distance I get is between two points: the chessboard and the camera. My question is where is the origine of my camera?

I know perfectly about my Chessboard but not my camera in terms of reference.

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As far as I understand camera calibration, the camera origin is on the focal point, which is the projection center. This topic has nice figure illustrating this. So my guess is that the distance is between the object point (your pattern position) and the projection center. @Tetragramm has the necessary experience to confirm this I guess.

StevenPuttemans gravatar imageStevenPuttemans ( 2017-04-14 04:52:11 -0500 )edit

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answered 2017-04-14 16:55:49 -0500

Tetragramm gravatar image

I'm not actually sure (I haven't been in a situation where it mattered), but I believe that it is the point of convergence in the lens system. In other words, centered in the lens, 1 focal length in front of the focal plane.

There's an image HERE that shows things nicely, but I don't know if there's still abstraction going on here.

It might also be 1 focal length in behind that point, along the optical axis, which would be the where the optical axis intersects the focal plane, but I don't think so.

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Asked: 2017-04-13 08:45:43 -0500

Seen: 146 times

Last updated: Apr 14 '17